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Two cyclists, 45 miles apart, start riding towards each other at the same time……..

Two cyclists, 45 miles apart, start riding towards each other at the same time……..-example-1
User Sidhuko
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1 Answer

26 votes
26 votes

Given:

Two cyclists, 45 miles apart, start riding towards each other at the same time.

Required:

We need to write the equation using the given information and to calculate the speeds of two cyclists.

Step-by-step explanation:

(a)

Let us consider r is the speed of slower cyclist.

Distance covered by slower cyclist,


r*3

Distance covered by faster cyclist,


2* r*3

Total distance is 45 miles.

Now from this data, we can say that


\begin{gathered} 2* r*3+r*3=45 \\ 6r+3r=45 \\ 9r=45 \end{gathered}

(b)

From part (a)


9r=45

By simplifying, we get


\begin{gathered} r=(45)/(9) \\ r=5 \end{gathered}

This is the Speed of the slower cyclist.

Hence speed of the faster cyclist is 2 times as fast as the slower cyclist.

Therefore, speed of the faster cyclist is


\begin{gathered} =2*5 \\ =10 \end{gathered}

Final Answer:

(a)


6r+3r=45

(b)

The speeds of both the cyclists is 5 miles per hour and 10 miles per hour.

User Debe
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