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You may need to use the appropriate appendix table or technology to answer this question. An agency reports that 11.4% of workers in a particular country belonged to unions. Suppose a sample of 300 workers is collected to determine whether union efforts to organize have increased union membership. If the sample results show that 42 of the workers belonged to unions, what is the p-value for your hypothesis test? Find the value of the test statistic. (Round your answer to two decimal places.)

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Final answer:

The p-value in this context is the probability of observing a sample proportion of union membership as extreme as 0.14 or more if the true population proportion is 0.114. The test statistic is calculated using a standard formula for a single proportion z-test. The exact p-value would be found using the calculated z-value and a z-table or statistical software.

Step-by-step explanation:

To determine the p-value for the hypothesis test regarding union membership, we start by stating the null hypothesis that the proportion of workers in unions is equal to the reported proportion of 11.4%. The alternative hypothesis would be that the proportion has increased. The sample proportion (p') from the 300 workers is 42/300 = 0.14. The test statistic for a proportion is calculated using the formula:

z = (p' - p0) / sqrt(p0(1-p0)/n)

Where:

  • p0 = 0.114 (reported proportion)
  • n = 300 (sample size)

Substituting the values:

z = (0.14 - 0.114) / sqrt(0.114(1-0.114)/300)

Upon calculation, the test statistic z-value is obtained. To find the p-value, we use the z-value and with technology or a z-table, we can determine the probability of observing a sample proportion as extreme as 0.14, if the true proportion is indeed 0.114. This p-value is then compared to the significance level (which was not provided in the question), and if the p-value is less than the significance level, we reject the null hypothesis. The p-value is the probability of observing a test statistic as extreme as the sample's, assuming the null hypothesis is true. For this specific case, because the actual numbers are not given, the p-value would be compared against the predetermined significance level to make a decision regarding the null hypothesis.

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