Final answer:
To supply 1kVA of power to a load with an efficiency of 95%, the transformer must be supplied with 1.053 kVA of power on the primary side, so the correct answer is a. 1.053 kVA.
Step-by-step explanation:
The question asks, "To deliver 1kVA of power to a load with an efficiency of 95%, how much power must be supplied to the transformer on the primary side?" The correct answer to this problem requires an understanding of how transformer efficiency affects power input.
Efficiency (η) of a transformer is defined as the ratio of power output (Ps) to power input (Pp). In mathematical terms, η = (Ps / Pp) × 100%. With an efficiency of 95%, and a power delivery of 1kVA (which is the power output), we can calculate the power input as follows:
Ps = 1kVA
η = 95%
Pp = Ps / (η / 100%)
Pp = 1 kVA / (95 / 100)
Pp = 1 kVA / 0.95
Pp = 1.053 kVA
The correct answer is a. 1.053 kVA, which is the amount of power that needs to be supplied on the primary side to deliver 1 kVA of power to the load when considering the transformer's efficiency.