Final answer:
To find the transfer function G(s) = C(s)/R(s), the Laplace transform is applied to the differential equation given by the student, resulting in a ratio of polynomials in 's', which represents the transfer function.
Step-by-step explanation:
The student's question is related to finding the transfer function G(s) = C(s)/R(s) from a given differential equation. To derive this transfer function, we apply the Laplace transform to both sides of the differential equation, taking into consideration that the Laplace transform of a derivative is sn multiplied by the Laplace transform of the function itself, minus the initial conditions (which are not given and therefore assumed to be zero). The detailed equation given is:
d3c/dt3 + 3 d2c/dt2 + 7 dc/dt +5c = d2r/dt2 + 4 dr/dt + 3r.
Applying the Laplace transform to each term and assuming the initial conditions are zero (since they are not provided), we get:
s3C(s) + 3s2C(s) + 7sC(s) + 5C(s) = s2R(s) + 4sR(s) + 3R(s).
Rearranging for C(s)/R(s), we obtain the transfer function:
G(s) = (s2 + 4s + 3) / (s3 + 3s2 + 7s + 5).