Question

A piece of a lossless RG-59B/U Coaxial cable has a nominal capacitance of 0.8 pF/meter, and inductance is 15 nH/m. If the diameter of the inner conductor as 0.8m, and the dielectric constant of the insulation is 4 then find the diameter of the outer conductor in cm?

Answer 1

The diameter of the outer conductor of the coaxial cable is 2.93 cm.

Step-by-step explanation:

The diameter of the outer conductor of a coaxial cable can be calculated using the formula:

Diameter of outer conductor = Diameter of inner conductor + 2 x (Nominal capacitance / (2π x Inductance x Dielectric constant))

Substituting the given values:

Diameter of outer conductor = 0.8m + 2 x (0.8 pF/m × 1 × 10^-12 F/pF / (2π × 15 nH/m × 1 × 10^-9 H/nH × 4))

Diameter of outer conductor = 0.8m + 2 x 1.0666667 cm

Diameter of outer conductor = 0.8m + 2.13 cm = 2.93 cm