Final answer:
To calculate the period of the waveform for the given test signal, we identify the frequency from the equation and use the relationship T = 1/f. the frequency is 296 Hz, thus the period is approximately 0.0034 seconds or 3.4 milliseconds.
Step-by-step explanation:
The question asks us to calculate the period of the waveform for the test signal v = 8.9 sin 2π ²⁹⁶ᵗ (V). The general form of a sinusoidal wave function is y(x, t) = A sin(kx – ωt), where ω is the angular frequency. From this, we can understand that the frequency f is the reciprocal of the period T (f = 1/T). to find the period of the waveform, we can rewrite the given equation as v(t) = 8.9 sin(2π (296)t). Here, the number 296 represents the frequency f in Hz. Therefore, the angular frequency ω is 2π × 296 rad/s. Consequently, the period T can be calculated by taking the reciprocal of the frequency:
T = 1/f.
T = 1/296, which roughly equals 0.0034 seconds or 3.4 milliseconds.