Question

We need to find the probability that at least two of the six members of a family are not born in fall if all the seasons have the same probability of containing the birthday of a person is selected randomly.

To find the probability that at least two of the six members of a family are not born in fall, we find the probability that at most four of the six members of a family are born in fall.

Since there are six members in the family, we have.

Since there are four seasons in a year, the probability to born in the fall season is.p=1/4

Answer 1

To find the probability that at least two of the six members of a family are not born in fall, we use the complement rule. The probability can be found by subtracting the probability that all six members are born in fall from 1.

Step-by-step explanation:

To find the probability that at least two of the six members of a family are not born in fall, we can use the complement rule. First, let's find the probability that all six members are born in fall. Since the probability for each member to be born in fall is 1/4, the probability for all six members to be born in fall is (1/4) * (1/4) * (1/4) * (1/4) * (1/4) * (1/4). The complement of this event is the probability that at least two of the six members are not born in fall, which is 1 - (1/4)^6.