Question

Assume that a resistive load of 100ohm is being fed by a voltage source of 34500 Volts rms. If the reactance of the line between the source and the load is 250ohm, a) Find the load current, load voltage, and the load power

Answer 1

To find the load current, we can use Ohm's law with the given voltage and resistance. The load voltage can be calculated using the voltage divider rule. The load power can be found using the formula P = I² * R. The result is 11.97 MW

Step-by-step explanation:

To find the load current, we can use Ohm's law which states that the current (I) is equal to the voltage (V) divided by the resistance (R). In this case, the voltage is 34500 V and the resistance is 100 ohms. So the load current is:

I = V / R = 34500 / 100 = 345 A

To find the load voltage, we can use the voltage divider rule which states that the voltage across a resistor is proportional to its resistance compared to the total resistance. In this case, the reactance of the line (250 ohms) is in series with the load resistance (100 ohms). So the load voltage is:

Vload = Vrms * (Rload / (Rload + X)) = 34500 * (100 / (100 + 250)) = 10350 V

Lastly, to find the load power, we can use the formula P = I² * R. In this case, the load power is:

P = I² * R = 345² * 100 = 11.97 MW