Final answer:
To produce a 10kHz square wave output with a 555 timer, one needs to connect resistors and a capacitor to the timer in an astable configuration using formulas to calculate the proper values for a 5V system clock.
Step-by-step explanation:
The task is to produce a system clock using a 555 timer to create a 5V square wave output with a frequency of 10kHz. A 555 timer can be configured in the astable mode to produce a continuous series of pulses, that is, a square wave. This is achieved by connecting resistors and a capacitor in the correct configuration with the 555 timer to set the desired oscillation frequency.
To achieve the 10kHz frequency with a 5V supply, provided the DC power supply parameters and the amplifier adjustments allow, standard formulas for the 555 timer in astable mode can be used: T = 0.693 * (R1 + 2 * R2) * C and f = 1 / T, where T is the time period, f is the frequency, R1 and R2 are resistors, and C is the capacitor. To obtain a 10kHz frequency, the values of R1, R2, and C must be chosen such that the time period T corresponds to 1/10000 seconds.