Final answer:
The output from the connected 8-Bit DAC, when the 10-Bit ADC is given an input of 3.4 V, would be approximately 6.79 V. The 10-Bit ADC has a resolution of approximately 0.004887 V per bit, and the system resolution is limited by the 8-Bit DAC, which is approximately 0.0392 V per bit.
Step-by-step explanation:
When dealing with 10-Bit ADC and 8-Bit DAC systems, it's important to understand the resolution of each device. The resolution is the smallest change in voltage that can be detected by an ADC or represented by a DAC.
The resolution for a 10-Bit ADC with a 5 V reference is calculated as Voltage Reference divided by the number of possible levels (210 - 1, since we start counting from 0). This gives us 5 V / 1023 ≈ 0.004887 V per bit.
Given an input voltage of 3.4 V, the ADC would output a digital value of 3.4 V / 0.004887 V per bit ≈ 695.7. We truncate this to 695 since an ADC provides an integer.
To find the output from the connected 8-Bit DAC, first we calculate the resolution for the DAC which has a 10 V reference. Thus, 10 V / 255 ≈ 0.0392 V per bit. The digital input value is then scaled to the DAC's resolution by multiplying the ADC's output value by the ratio of the resolutions of the two devices. So, to find the DAC equivalent output, we would calculate (695 / 1023) * 255, which gives us approximately 173.25. This would be then scaled according to the 10 V reference, resulting in a DAC output of 173.25 * 0.0392 V per bit ≈ 6.79 V.
Finally, the system resolution refers to the resolution of the overall system, which is limited by the device with the lower resolution. In this case, it's the 8-Bit DAC since it has fewer bits to represent values. The overall system resolution then is approximately 0.0392 V per bit.