Question

Design a circuit using a 74150 multiplexor that will output a HIGH whenever a month has 31 days. The month number (1 to 12) is input as a 4-bit binary number (January = 0001 and so on)

Answer 1

To design a circuit using a 74150 multiplexor that outputs a HIGH when a month has 31 days, connect the inputs of the multiplexor to represent the months with 31 days, and use a 4-bit binary number as the month input.

Step-by-step explanation:

To design a circuit using a 74150 multiplexor that will output a HIGH whenever a month has 31 days, we can utilize the fact that there are only seven months with 31 days: January, March, May, July, August, October, and December. We can connect the inputs of the multiplexor to represent these months and use a 4-bit binary number as the month input. The truth table for the multiplexor would have a HIGH output for the binary inputs corresponding to these seven months, i.e., 0001, 0011, 0101, 0111, 1000, 1010, and 1100.

If the month input matches any of these binary inputs, the multiplexor will select the corresponding HIGH output and provide it as the output of the circuit. If the month input does not match any of these binary inputs, the multiplexor will select a LOW output, indicating that the month has fewer than 31 days.

So, the circuit using a 74150 multiplexor will output a HIGH whenever a month has 31 days, based on the 4-bit binary representation of the month input.