Question

For the following code

#include

int sumGlobal = 0;

int sum(int, int);

main()

{

int value = sum(2, 7);

printf(sum=%d\\, value);

value = sum(2, 13 );

printf(sum=%d, value);

} //end main function

int sum(int n1, int n2) {

for (int i = n1; i <= n2; i++) {

sumGlobal += i;

}

return sumGlobal;

}




Find 'value'.

value =

Answer 1

The value of the variable 'value' after executing the code is 104. The 'sum' function computes a running total including previous calls as it updates a global variable, 'sumGlobal', which accumulates the sum of integers between two given values.

Step-by-step explanation:

The student is asking to calculate the variable value after executing the provided C code snippet. This code defines a global variable sumGlobal and a sum function that calculates the cumulative sum between two integer parameters n1 and n2. When the sum function is called, it adds the numbers from n1 to n2 to sumGlobal and returns the updated value of sumGlobal.

When sum is first called with (2, 7), the function processes the numbers 2 through 7, which equates to a sum of 27 (2+3+4+5+6+7).

Thus, value is set to 27 after the first call. Subsequently, sum is called again with (2, 13) without resetting sumGlobal, which means we start adding to the existing sum of 27. The second sum equates to 77 (2+3+4+...+13), which is then added to the first sum, totaling 104 (27 + 77). After the second call, value becomes 104. Therefore, after the completion of the code, the value of value is 104.