Final answer:
To design a buck converter for the specified conditions, one must calculate appropriate values for the inductor and capacitor to create an LC filter that maintains a voltage ripple under 100mV and an LIR ≤0.25, then simulate the design using tools like SPICE to verify compliance with the requirements.
Step-by-step explanation:
Designing a Buck Converter
To design a buck converter for the given specifications, we will calculate the required inductor (L) and capacitor (C) values for the LC filter. The converter is required to operate with a load impedance between 0.1Ω and 10Ω, a clock frequency of 1MHz, an output voltage of 2.5V, an input voltage from a battery of 5V, and components considered to be ideal. We aim for a voltage ripple not exceeding 100mV and a Load Inductance Ratio (LIR) of less than or equal to 0.25.
First, we choose the inductor value to ensure the current ripple meets the LIR criterion. The inductance (L) and capacitance (C) values are then calculated based on the desired ripple voltage and current, and the switching frequency. Using these values, an LC filter is designed to smooth out the voltage ripple to the desired level. The process often involves iterating the design choices to meet all specifications after initial calculations. For the voltage ripple, the capacitor value would also need to be selected properly. Finally, simulation tools like SPICE can be used to test the converter's performance and ensure it complies with the stated requirements.