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A black box with an input and output is found to have a voltage gain magnitude |H(jω₀)| = 25 at a frequency ω₀, with vout lagging vin by 55 degrees (both voltages are sinusoids). (10 pts.)

a) Express the gain at ω₀ as a complex number in both Cartesian and polar (Euler) form. Be careful with the difference between radians and degrees.

User Koen Bok
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Final answer:

The complex gain of the black box at frequency ω₀ is 14.34 - j*20.48 in Cartesian form, and 25 ∠ -55 degrees in polar form, with 'j' representing the imaginary unit, and the angle given in degrees to indicate the phase lag.

Step-by-step explanation:

The gain of a black box at a specific frequency ω₀ is given as a magnitude |H(jω₀)| = 25 with the output voltage lagging the input voltage by 55 degrees. To express this gain as a complex number in Cartesian and polar forms, we can use the magnitude and phase shift information provided.

In Cartesian form, the complex gain H(jω₀) will have a real part 'a' and an imaginary part 'b' such that a + j * b is equivalent to the polar form with magnitude 25 and phase -55 degrees. The negative sign in the phase indicates lag between the output and input.

The conversion from polar to Cartesian form is given by the equations:

a = |H| * cos(ϕ) = 25 * cos(-55 degrees)

b = |H| * sin(ϕ) = 25 * sin(-55 degrees)

After calculating, we have:

a ≈ 25 * cos(-55 degrees) ≈ 14.34

b ≈ 25 * sin(-55 degrees) ≈ -20.48

Thus, in Cartesian form, the gain H(jω₀) = 14.34 - j*20.48. To express this in polar form, we can use the magnitude and phase directly as:

H(jω₀) = 25 ∠ -55 degrees.

Note that in this context, degrees are used rather than radians for the phase angle.

User RelativeGames
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