Final answer:
To find the voltage in Node 1, we need to calculate the current flowing through each resistor and then use Ohm's law to determine the voltage drop across each resistor. The voltage in Node 1 is 103.23V.
Step-by-step explanation:
The total voltage in Node 1 can be determined using node analysis. Node 1 is connected to three resistors: R1, R2, and R3. To find the voltage in Node 1, we need to calculate the current flowing through each resistor and then use Ohm's law to determine the voltage drop across each resistor.
First, let's find the total resistance, which is the sum of R1, R2, and R3. The total resistance is 10Ω + 6Ω + 15Ω = 31Ω.
Next, we can use Ohm's law to find the current flowing through R2. The voltage across R2 is given as 20V, and the resistance is 6Ω. Using Ohm's law (V = I * R), we can calculate the current as I = V/R = 20V / 6Ω = 3.33A.
Using the calculated current, we can then find the voltage drops across each resistor. The voltage drop across R1 is V = I * R = 3.33A * 10Ω = 33.3V. The voltage drop across R2 is V = I * R = 3.33A * 6Ω = 19.98V. The voltage drop across R3 is V = I * R = 3.33A * 15Ω = 49.95V.
Finally, to find the voltage in Node 1, we can add up the voltage drops across each resistor: 33.3V + 19.98V + 49.95V = 103.23V. Therefore, the voltage in Node 1 is 103.23V.