Final answer:
To calculate the maximum amplitude of a wave at 10 meters in wood, the attenuation formula A = A0 * e^(-α * x) is used. Given an initial amplitude of 5 V/m and an attenuation constant of 0.086, the maximum amplitude at 10 meters is approximately 2.22 V/m.
Step-by-step explanation:
The query concerns calculating the maximum wave amplitude of a wave at a distance of 10 meters in wood, given the initial wave amplitude, the frequency, the attenuation constant (α), and the phase constant (β). The propagation of waves, such as electromagnetic waves in different media, involves attenuation, which leads to a decrease in amplitude over distance. The attenuation constant (α) represents how quickly the amplitude of the wave decreases as it propagates through the material.
Using the formula for wave attenuation, the maximum wave amplitude A at a given distance x can be calculated as A = A0 * e^(-α * x), where A0 is the initial amplitude and x is the propagation distance. In this specific scenario, with A0 being 5 V/m, α being 0.086, and the distance x being 10 meters, the maximum amplitude A at 10 meters would be: A = 5 V/m * e^(-0.086 * 10 m).
After calculating, we find that the maximum amplitude of the wave at a distance of 10 meters in wood is approximately 2.22 V/m.