Question

The voltage v(t) = 359.3 cos(ωt) volts is applied to a load consisting of a 10-Ω resistor in parallel with a capacitive reactance XC = 25 Ω.

Calculate the instantaneous power absorbed by the resistor.

Answer 1

To calculate the instantaneous power absorbed by the resistor in this circuit, the current flowing through the resistor and the voltage across it needs to be found. Using Ohm's law, calculated to be 35.93 A. The instantaneous power absorbed by the resistor is calculated to be 12,939.5 W.

Step-by-step explanation:

To calculate the instantaneous power absorbed by the resistor in this circuit, we need to find the current passing through the resistor and the voltage across it. The current flowing through the resistor can be calculated using Ohm's law, which states that I = V/R, where I is the current, V is the voltage, and R is the resistance. The voltage across the resistor is the same as the applied voltage. So, the current passing through the resistor is 359.3/10 = 35.93 A. The instantaneous power absorbed by the resistor can be calculated using the formula P = VI, where P is power, V is voltage, and I is current. Substituting the values, we get P = 359.3*35.93 = 12939.5 W.