Question

How many turns are required to produce 23.0 mH with a coil wound on a cylindrical core having a cross-sectional area of 13 * 10⁻⁵ mi² and a length of 35 cm? The core has a permeability of 1.2×10⁻⁶ H/m. The result should be in turns. Calculate answers to the nearest whole number.

Answer 1

Approximately 11,166 turns are required to produce a 23.0 mH inductance with the given coil.

Step-by-step explanation:

To calculate the number of turns required to produce a specific inductance in a coil, we can use the formula:

N = (L * A) / (μ * x)

Where:

N is the number of turns,

L is the inductance in henries,

A is the cross-sectional area of the core in square meters,

μ is the permeability of the core material in henry per meter, and

x is the length of the coil in meters.

Substituting the given values:

N = (23.0 * 0.00013) / (1.2e-6 * 0.35)

Simplifying the expression:

N ≈ 11,166

Therefore, approximately 11,166 turns are required to produce a 23.0 mH inductance with the given coil.