Question

One sine wave (Wave-A) has the first positive peak at 105 and another (Wave.-) has the first positive peak at 80. What is the phase angle between them?

Use positive numbers if Wave- B is leading and negative numbers if Wave- B is lagging.
The result should be in degrees.
Calculate Answers to 2 decimal points.

Answer 1

The phase angle between Wave-A and Wave-B is +25 degrees, indicating that Wave-B is leading Wave-A by 25 degrees.

Step-by-step explanation:

To determine the phase angle between two sine waves (Wave-A and Wave-B) with positive peaks at 105 and 80 respectively, we need to compare their peak positions. Assuming each wave has a period of 360 degrees (since we're dealing with degrees, not radians), the difference in peak positions is the phase shift between them.

Wave-B's peak is at 80, and Wave-A's peak is at 105. To find the phase difference, we subtract the peak position of Wave-B from that of Wave-A:

Phase difference = 105 - 80 = 25 degrees.

Since Wave-B reaches its peak before Wave-A, Wave-B is leading. Thus, the phase angle is +25 degrees, indicating that Wave-B is leading by 25 degrees.