Question

The A-connected source of Problem 2 is connected to a Y-connected load by means of a balanced three-phase distribution line. The load impedance is 957+j 259 2 per phase. And the line impedance is 1.2+j12 Ω per phase.

Construct a single-phase equivalent circuit of the system.

Answer 1

To construct a single-phase equivalent circuit of the system, convert the Y-connected load into an equivalent Delta-connected load by using the formula: Zdelta = ZY/3. Substituting the given values, the single-phase equivalent circuit consists of the A-connected source and the Delta-connected load, connected by the balanced three-phase distribution line.

Step-by-step explanation:

To construct a single-phase equivalent circuit of the system, we need to convert the Y-connected load into an equivalent Delta-connected load. The impedance of the Delta-connected load can be found using the formula:

Zdelta = ZY/3

Substituting the given values, we get:

Zdelta = (957+j2592)/3 = 319+j864 Ω per phase

The single-phase equivalent circuit consists of the A-connected source and the Delta-connected load, connected by the balanced three-phase distribution line. The line impedance remains the same.