118k views
1 vote
Suppose, the address 7500H: BFD2H has an instruction. To execute

the instruction, what should be the value of CS if IP is (i) AB22H
(ii) BFDAH

User Ocramius
by
7.1k points

1 Answer

2 votes

Final answer:

To execute the instruction at address 7500H: BFD2H, we need to determine the value of CS.

Step-by-step explanation:

The address 7500H: BFD2H represents a segment address and an offset address. In the 8086 assembly language, the segment address is represented by the CS (Code Segment) register, and the offset address is represented by the IP (Instruction Pointer) register. To execute the instruction at address 7500H: BFD2H, we need to determine the value of CS.

(i) If IP is AB22H, then the value of CS can be calculated as follows:

  1. IP = AB22H
  2. Segment address = 7500H
  3. CS = Segment address - IP = 7500H - AB22H = 609EH

(ii) If IP is BFDAH, then the value of CS can be calculated as follows:

  1. IP = BFDAH
  2. Segment address = 7500H
  3. CS = Segment address - IP = 7500H - BFDAH = 15426H
User Peterchen
by
8.8k points