Question

A 220 V DC Motor has an armature resistance of 0.2 Ω. At no-load, the motor runs at 1000 RPM. Under rated load, the motor draws an input power of 11 kW while running at a speed of 960.7 RPM. Compute the following for the DC motor: a) Speed regulation

Answer 1

To calculate the speed regulation of a DC motor, we need to find the difference between the no-load speed and the speed under rated load, and then divide that difference by the no-load speed.

Step-by-step explanation:

In order to calculate speed regulation, we need to determine the difference between the no-load speed and the speed under rated load, and then divide that difference by the no-load speed.

The no-load speed is given as 1000 RPM, and the speed under rated load is given as 960.7 RPM. Therefore, the difference is 1000 RPM - 960.7 RPM = 39.3 RPM.

To calculate the speed regulation, we divide the difference by the no-load speed and multiply by 100 to get the percentage. Therefore, the speed regulation is (39.3 RPM / 1000 RPM) * 100 = 3.93%.