172k views
4 votes
The Field And Armature Resistances Of A Series 320 V Dc Motor Are Rse=0.35Ω, And Ra=0.25Ω. The Motor Draws 50 A From Supply, While Running At 800rpm. If The Constant Losses Are 500 W, Calculate: Draw And Label A Complete Circuit Diagram →

The Efficiency Of The Motor At This Load %Η=

User Gliljas
by
8.1k points

1 Answer

2 votes

Final answer:

To calculate the efficiency of the motor at this load, use the formula %Η = (Power output / Power input) x 100%. First, calculate the voltage across the motor, then calculate the power output and power input. Finally, use the efficiency formula to find the percentage.

Step-by-step explanation:

The efficiency of a motor can be calculated using the formula:

%Η = (Power output / Power input) x 100%

To calculate the power output, we can use the formula:

Power output = (Voltage across the motor - Back emf) x Current

First, we need to calculate the voltage across the motor:

Voltage across the motor = Voltage supply - (Field resistance x Current)

Substituting the given values:

Voltage across the motor = 320V - (0.35Ω x 50A)

Next, we can calculate the power output:

Power output = (320V - (0.35Ω x 50A) - (0.25Ω x 50A)) x 50A

To calculate the power input, we can use the formula:

Power input = Voltage supply x Current

Substituting the given values:

Power input = 320V x 50A

Finally, we can calculate the efficiency using the formulas above:

%Η = (Power output / Power input) x 100%

Remember to convert the answer to a percentage to get the efficiency of the motor at this load.

User Binder
by
7.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.