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10*(-6-9i)=?

Your answer should be a complex number in the form a + bi where a and b are real numbers.

From khan

1 Answer

6 votes

Final answer:

The product of 10*(-6-9i) is -60 - 90i, which is the standard form for complex numbers a + bi, where a and b are real numbers.

Step-by-step explanation:

The question of a complex multiplication problem, which is to calculate 10*(-6-9i).

To solve this, we apply distribution of the real number over the complex number.

Multiplying the real part and the imaginary part separately with 10 gives:

  • 10 * (-6) = -60
  • 10 * (-9i) = -90i

Therefore, the product is -60 - 90i, which is already in the standard form a + bi for complex numbers where a is the real part and b is the coefficient of the imaginary part i.

User Andrew Eisenberg
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