Question

A 60−(MHz) electromagnetic wave exists in an air-dielectric coaxial cable having an inner conductor with radius a and an outer conductor with inner radius b. Assuming perfect conductors, and the phasor form of the electric field intensity to be E = aᵣE₀/r e⁻ʲᵏᶻ(V/m), a < r < b

find k?

Answer 1

To find the value of k in the given expression for the electric field intensity E = arE₀/re⁻ʲᵏᶻ (V/m), we need to consider the wave equation and compare it to the given expression. In the wave equation, k represents the wavenumber, which is defined as 2π divided by the wavelength λ.

Step-by-step explanation:

To find the value of k in the given expression for the electric field intensity E = arE₀/re⁻ʲᵏᶻ (V/m), we need to consider the wave equation and compare it to the given expression. In the wave equation, k represents the wavenumber, which is defined as 2π divided by the wavelength λ. So, we can write k as 2π/λ. Since the question provides information about the radius a < r < b, the value of r in the given expression can be considered as the distance from the center of the coaxial cable to any point within that range. Using the relationship between the wavenumber and the wavelength, we can determine the value of k.