Final answer:
To solve the given second-order linear homogeneous differential equation, we assume a solution of the form v(t) = e^rt and find the characteristic equation. The general solution is v(t) = C1e^-2t + C2e^-3t. The values of C1 and C2 can be determined using the initial conditions.
Step-by-step explanation:
The given differential equation is a second-order linear homogeneous differential equation. To solve it, we can assume a solution of the form v(t) = ert. Plugging this into the differential equation, we can find the characteristic equation:
r2 + 5r + 6 = 0
Factoring the equation as (r + 2)(r + 3) = 0, we find two distinct roots: r = -2 and r = -3. Therefore, the general solution to the differential equation is v(t) = C1e-2t + C2e-3t. To find the values of C1 and C2, we can use the initial conditions.