Final answer:
The cutoff frequency of a single-section RC low-pass filter with R = 4.8 kΩ and C = 0.0028 μF is approximately 14.04 kHz.
Step-by-step explanation:
The cutoff frequency (f∞) of a single-section RC low-pass filter can be calculated using the formula f∞ = 1/(2πRC), where R is the resistance and C is the capacitance. In this case, with R = 4.8 kΩ (which is 4800 Ω) and C = 0.0028 μF (which is 2.8×10-9 F), the cutoff frequency can be found by substituting the given values into the formula.
f∞ = 1/(2π(4800 Ω)(2.8×10-9 F))
Calculating this yields:
f∞ = 1/(2π(4800)(2.8×10-9)) ≈ 14.04 kHz
Therefore, the cutoff frequency of the low-pass filter is approximately 14.04 kHz.