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Write logb((x²y) / (z³)) in terms of logarithms of x,y, and z given that x > 0, y > 0, and z > 0.

User Bartuzz
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Final answer:

The expression logb((x²y) / (z³)) can be written as (2 × logb(x)) + logb(y) - (3 × logb(z)) using the properties of logarithms of products, quotients, and exponents.

Step-by-step explanation:

The student asked to write logb((x²y) / (z³)) in terms of logarithms of x, y, and z. By using the properties of logarithms, we can simplify this expression step by step.

Firstly, using the property that the logarithm of a division is the difference between the logarithms we write:

logb((x²y) / (z³)) = logb(x²y) - logb(z³)

Next, we apply the property that the logarithm of a product is the sum of the logarithms:

logb(x²y) = logb(x²) + logb(y)

For the terms with exponents, apply the property that the logarithm of a number raised to an exponent is the product of the exponent and the logarithm:

logb(x²) = 2 × logb(x)

logb(z³) = 3 × logb(z)

Combining these, we get the final expression:

logb((x²y) / (z³)) = (2 × logb(x)) + logb(y) - (3 × logb(z))

User Blazej SLEBODA
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