Question

there are three inductors L1=37mH, L2=50mH, and L3=21mH connected in series. What is the value of their equivalent inductance in mH?

Answer 1

When inductors are connected in series, their equivalent inductance is the sum of their individual inductances. In this case, the equivalent inductance is 108 mH.

Step-by-step explanation:

When inductors are connected in series, their equivalent inductance is the sum of their individual inductances.

To find the equivalent inductance, we add the values of L1, L2, and L3:

Leq = L1 + L2 + L3

Substituting the given values, Leq = 37 mH + 50 mH + 21 mH = 108 mH

Therefore, the value of the equivalent inductance is 108 mH.