Final answer:
The phase current and line current in a balanced three-phase ∆-∆ circuit, with each phase having a power load of 10kW and a reference source voltage of 120°0° V, are both 83.33 A.
Step-by-step explanation:
The question deals with finding the phase and line currents in a balanced three-phase ∆-∆ (delta-delta) circuit where each phase of the load is dissipating 10 kW of power, and the reference source voltage is given as 120°0° V.
To calculate the phase current (Iphase), we use the power formula P = Vphase * Iphase * cos(φ), where Vphase is the phase voltage and the power factor cos(φ) is assumed to be 1 for a purely resistive load. Since this is a ∆ circuit, the phase voltage is equal to the line voltage, which is 120 V.
Therefore, the phase current Iphase is P/V = 10,000 W / 120 V = 83.33 A. For a ∆-∆ circuit, the line current Iline is the same as the phase current, so Iline also equals 83.33 A.