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Find the exact solution algebraically, log₅ (4x-7)=4

User Borrible
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Final answer:

To solve the equation log₅ (4x-7)=4, we convert it to the exponential form 5⁴ = 4x - 7, simplify the equation, and isolate x to find x = 158.

Step-by-step explanation:

To find the exact solution algebraically for the equation log₅ (4x-7)=4, we need to apply the properties of logarithms to solve for the variable x.

First, we convert the logarithmic equation to its exponential form. This is based on the definition of a logarithm, which in this case can be written as 5 to the power of 4 equals 4x - 7:

5⁴ = 4x - 7

Now, simplify the equation by performing the exponentiation:

625 = 4x - 7

Next, we apply basic algebra to isolate x:

625 + 7 = 4x632 = 4x

Divide both sides of the equation by 4 to solve for x:

x = 158

We have found the solution, x = 158.

User Gkof
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