Final answer:
The transfer function H(s)=1/(1+0.001×s) can be plotted on the complex s plane with its amplitude highest at the single pole (s=-1000) and decreasing with distance from it. In the Bode plot, the amplitude begins with 0 dB gain and decreases past the corner frequency (1 kHz), while the phase starts at 0° and approaches -90° at high frequencies.
Step-by-step explanation:
To plot the transfer function H(s) = 1 / (1 + 0.001 × s) on the complex s plane and Bode plot:
This transfer function represents a first-order system with a single pole at s = -1000. On the complex s plane, the amplitude will be highest at the pole and decreases as we move away from it. Since it is a simple pole, the plot will resemble a set of concentric circles centred on the pole, with amplitude decreasing with increasing distance from the pole.
The Bode plot will show how the amplitude and phase of the transfer function vary with frequency. The amplitude plot will start off with 0 dB gain at low frequencies and begin to decrease at a rate of 20 dB/decade once we pass the corner frequency (1 kHz). The phase plot will start at 0° at low frequencies and approach -90° as frequency increases.