Final answer:
In a synchronous TDM system, a demultiplexer distributes a 16-bit input slot to multiple output lines by assigning each bit to an output channel based on its time slot. Without information on the number of output channels, the specific bit stream for each output cannot be fully determined.
Step-by-step explanation:
The question revolves around the function of a demultiplexer (DEMUX) in a synchronous Time Division Multiplexing (TDM) system. Given a 16-bit input slot without framing bits, a DEMUX segregates this bit stream into multiple output lines, assigning each bit to the correct output channel based on the 'time slot' it was received in. In a synchronous TDM, the input is provided in a structured manner with each channel being allocated a fixed time slot in a cyclic order.
If the input stream is presented as 1001110010100000, 1010101010100001, 0111000001111000 not considering framing or other control bits, each output channel would receive a bit one after the other in sequence. Therefore, if the DEMUX has enough output lines, each line would get every nth bit, with n being the total number of outputs. For example, if there were 16 output channels, each output would receive one bit from each 16-bit slot, in the corresponding order. Without additional information about the configuration of the DEMUX, the specifics of the bit stream for each output cannot be fully determined.