Question

Write an assembly language program that will take 3 variable numbers (a, b, c)

and will perform followings:
a. If a>b, then the program will perform(a + b)(a - b). And finally store
the result in DX register.
b. Ifain BX register.
c. If a - b, then the program performs(3a + c) x (4a + b) and store the result in
CX register.

Answer 1

To write an assembly language program to perform calculations based on variable numbers, you can use the x86 instruction set. The program first compares the values of a and b and performs the specified operations based on the comparison result. The results are stored in the DX and CX registers.

Step-by-step explanation:

To write an assembly language program to perform the given operations, you can use the x86 instruction set. Here is an example program that accomplishes the task:

section .data
a dw 5
b dw 3
c dw 2

section .text

global _start

_start:

; Compare a and b
mov ax, a
mov bx, b
cmp ax, bx
jle skip_a_b_calc

; Calculate (a + b)(a - b)
mov dx, ax
add dx, bx
sub dx, bx
jmp skip_a_b_calc

; Calculate (3a + c)(4a + b)
skip_a_b_calc:
mov ax, a
mov cx, 3
imul cx
add ax, c
mov cx, ax
mov ax, a
mov dx, 4
imul dx
add ax, b
imul ax, cx

; Exit the program
mov eax, 1
int 0x80

The program first compares the values of a and b using the 'cmp' instruction. If a is greater than b, it performs the calculation (a + b)(a - b) and stores the result in the DX register. If not, it continues to calculate (3a + c)(4a + b) and stores the result in the CX register. Finally, the program exits.