Question

A Zener has an impedance of 15Ω. When I Z ​ = 25 mA, the voltage across the zener diode V ZD ​ = 47 V. What is the value of V ZD ​ when IZ ​ = 50 m

A. 5.45 V
B. 4.7 V
C. 5.83 V
D. 5.08 V

Answer 1

The impedance of the Zener diode can be calculated using the formula Z = VZD / IZ, where Z is the impedance, VZD is the voltage across the diode, and IZ is the current flowing through the diode. Using the given values, we can calculate the impedance of the Zener diode as 1880 Ω. To find the value of VZD when IZ = 50 mA, we can rearrange the formula to solve for VZD: VZD = Z * IZ. Plugging in the values, we get VZD = 94 V.

Step-by-step explanation:

Impedance is the opposition to the flow of an alternating current (AC) in a circuit. It is measured in ohms. The impedance of a Zener diode can be calculated using the formula Z = VZD / IZ, where Z is the impedance, VZD is the voltage across the diode, and IZ is the current flowing through the diode.

Using the given values, we can calculate the impedance of the Zener diode as 47 V / 25 mA = 1880 Ω.

To find the value of VZD when IZ = 50 mA, we can rearrange the formula to solve for VZD: VZD = Z * IZ. Plugging in the values, we get VZD = 1880 Ω * 50 mA = 94 V.