Using the Student's t-distribution, the conclusion is that the mean height of children in the community exposed to uranium tailings is significantly shorter than the mean height of children in nearby Native American communities at a significance level of .01.
The data scientist's test of significance = A t-test
Chosen significance level <01.
The mean height of children of the same age as the children in question living in nearby Native American communities = 43 inches
The number of children in the community exposed to uranium tailings, = 16 children
The mean height of these = 39 inches
The standard deviation = 3.5
Using the Student’s t-distribution on page A105 of the textbook, the formula for the t-test is:

The sample mean =
The population mean = μ
The sample standard deviation = s
The sample size = n
The null hypothesis (H₀): the mean height of children in the community exposed to uranium tailings is equal to the mean height of children in nearby Native American communities.
The alternative hypothesis (Hₐ): the mean height of children in the community exposed to uranium tailings is less than the mean height of children in nearby Native American communities.
The computation of the t-value is as follows:
t = (39 - 43) / (3.5 / √16) = -4.57
The critical value of t for a one-tailed test with 15 degrees of freedom and a significance level of .01 = -2.947.
Since the calculated t-value (-4.57) is less than the critical value (-2.947), we reject the null hypothesis and conclude that the mean height of children in the community exposed to uranium tailings is significantly shorter than the mean height of children in nearby Native American communities at a significance level of .01.