Question

Consider that the total duration of a finite pulse, T d , is the time of M=50 pulses. The pulse width of each pulse is 15μ s duration. The duty cycle d t is 8%. Calculate the - range resolution, - Doppler resolution - Maximum unmabiguous range associated with this waveform

Answer 1

The range resolution is 15μs, the Doppler resolution is 15μm/s, and the maximum unambiguous range is c / 25.

Step-by-step explanation:

The range resolution can be calculated by dividing the total duration of the pulse, Td, by the number of pulses, M. In this case, Td is 50 pulses * 15μs/pulse = 750μs. So the range resolution is 750μs / 50 = 15μs.

The Doppler resolution depends on the pulse width and the speed of the pulses. In this case, since the pulse width is 15μs and the pulses are traveling at 1 m/s, the Doppler resolution is the pulse width divided by the speed of the pulses, which is 15μs / 1 m/s = 15μm/s.

The maximum unambiguous range is given by the formula Rmax = c / (2 * PRF), where c is the speed of light and PRF is the pulse repetition frequency. Since the duty cycle dt is 8%, the PRF can be calculated as 100 / dt, which is 100 / 8 = 12.5. So the maximum unambiguous range is c / (2 * 12.5) = c / 25.