Question

Consider a monostatic radar transmitting pulses, where each pulse is a signal x(t)= Acos(2πf 0 t+θ) of duration τ=10μs, the PRF is 20KHz, the radar frequency is f 0 =8GHz, A=50 volts, and consider that the peak transmit power of a sinusoid signal is given by A 2

Watt. The radar's transmit and receive antenna gains are both given by G=22 dB. The dwell time is 24 ms. The target distance is 30Km and the radar cross section is 1.5 m 2 .

Assume negligible atmospheric 2 and system losses. The average transmit power in this problem will be given by A
2 times the duty cycle. - Calculate the received average power, P r , using radar range equation. - If A ′ = P r , what will be the expression for the received noiseless signal

Answer 1

The received average power (Pr) is calculated using the radar range equation, incorporating the given transmit power, antenna gains, radar cross section, and distance to the target. The received signal expression (A') is the same as the transmitted signal with an adjusted power level for the received power.

Step-by-step explanation:

To calculate the received average power (Pr), we can use the radar range equation, which considers transmit power, antenna gains, target distance, and radar cross section. Given that the peak transmit power is A2 watts, the duty cycle can be determined by dividing the pulse duration (τ) by the inverse of the pulse repetition frequency (PRF). The radar range equation is:

Pr = rac{Pt G2 σ λ2 }{(4π)3 R4 Lt Lr}

Assuming that losses (Lt and Lr) are negligible and applying the given numbers, the received average power can be calculated. To find the expression for the received signal (A' = Pr), we consider the same format as the transmitted signal but with the power level adjusted to the received power.