Question

An ideal transformer with N ₁ = 1000 and N ₂ = 250 is connected with an impedance Z22 across winding 2. If V₁ = 1000 ∠0° V and I₁ = 5, ∠-30°

A determine
V₂, I₂, Z₂ and the impedance Z¹₂, which is the value of Z₂ referred to the primary side of the transformer.

Answer 1

The problem involves calculations on an ideal transformer, focusing on parameters such as secondary voltage (V2), secondary current (I2), and impedances (Z2 and Z12) using the transformer equation.

Step-by-step explanation:

The question pertains to the functioning of an ideal transformer and involves calculating various parameters such as the secondary voltage (V2), secondary current (I2), secondary impedance (Z2), and the impedance referred to the primary side (Z12). Using the transformer equation, we know that the ratio of secondary to primary voltages is directly proportional to the turns ratio of the coils, and so is the inverse ratio for currents.

Given primary voltage V1 = 1000 ∠0° V, primary current I1 = 5 ∠-30° A, primary turns N1 = 1000, and secondary turns N2 = 250. The secondary voltage V2 can be found by V2 = V1 * (N2/N1). The secondary current I2 can be found by I2 = I1 * (N1/N2). The secondary impedance Z2 is simply V2/I2, and the impedance referred to the primary side Z12 is calculated by Z2 * (N1/N2)2.