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The chip-size of a CPU is 10 mm x 10 mm (square shape). Its clock frequency is 500 Hz and it operates at a supply voltage of 1V. The length of the clock routing is estimated to be 1.1 times the circumference (perimeter) of the chip. Assume that the clock signal is routed on a metal wire with a width of 0.5 nm and that the parasitic capacitance of the metal layer is 0.5aF/ nm2. What is the switching power dissipated due to the clock routing mechanism

User Puckl
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Final answer:

The switching power dissipated due to the clock routing mechanism can be calculated using a formula incorporating the chip size, clock frequency, supply voltage, and clock routing length.

Step-by-step explanation:

The switching power dissipated due to the clock routing mechanism can be calculated using the formula:

Switching Power = (Parasitic Capacitance * Clock Frequency * Supply Voltage^2 * Clock Routing Length) / Chip Size

Given that the chip size is 10 mm x 10 mm, the clock frequency is 500 Hz, the supply voltage is 1V, and the clock routing length is 1.1 times the circumference of the chip, we can substitute these values into the formula to calculate the switching power dissipated.

User Paladini
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