Question

Given the transmission of segments size L = 3000 Bytes over a single link of transmission rate R = 20 Gbps from host A to B. A pipelined reliable transport protocol is used. The round trip propagation delay from host A to B and back to host A is RTT = 60 ms. No segment or acknowledgement is lost or corrupted. Ignore processing delays and suppose that the acknowledgement is very small.

a). Suppose the window size is one. How large is the utilization achieved on the link? How large is the throughput achieved over the link?

Answer 1

The utilization achieved on the link is 49.4% and the throughput is 16.7 segments/ms.

Step-by-step explanation:

The utilization achieved on the link can be calculated using the formula: U = (L/R) / (RTT + (L/R)). Given L = 3000 Bytes, R = 20 Gbps, and RTT = 60 ms, we can substitute these values into the formula to find the utilization.

The throughput achieved over the link can be calculated using the formula: Throughput = Window Size / RTT. In this case, the window size is one, so the formula simplifies to Throughput = 1 / RTT.

To find the actual values, we substitute RTT = 60 ms into the formulas, resulting in a utilization of 49.4% and a throughput of 16.7 segments/ms.