Question

I need help with this practice problem solving This is trigIt has an additional pic that I will send you, it is the graph that goes along with this, use the graph to complete***

Answer 1

`f(x)=\sin x+2`

First, let's find the value of f(x) along the midline x = 0:

`\begin{gathered} f(0)=\sin 0+2 \\ f(0)=2 \end{gathered}`

Then, the point at the midline is (0,2)

The minimum point nearest the midline is:

`\begin{gathered} f(-(\pi)/(2))=_{}f(-1.57) \\ f(-(\pi)/(2))=\sin (-(\pi)/(2))+2 \\ f(-(\pi)/(2))=-1+2 \\ f(-(\pi)/(2))=1 \end{gathered}`

Analogously, the maximum point nearest the midline is:

`\begin{gathered} f((\pi)/(2))=_{}f(1.57) \\ f((\pi)/(2))=\sin ((\pi)/(2))+2 \\ f((\pi)/(2))=1+2 \\ f((\pi)/(2))=3 \end{gathered}`

Then the graph is given by: