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Complete the table to perform four iterations of the Secant Method.

i x(i-1) x(i) x(i+1) ea(%)
1 0.0000 - - 53900.00
8.0000 0.0148
2 - 50.13
0.0297
3 2.1883 101.36
4 1.3209 65.67

User KKlalala
by
7.3k points

1 Answer

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Final answer:

The Secant Method is an iterative numerical method used to find the roots of a function. It estimates the location of the root by linear interpolation. Four iterations of the Secant Method are performed using the given initial values.

Step-by-step explanation:

The Secant Method is an iterative numerical method used to find the roots of a function. It is based on linear interpolation between two initial points to estimate the location of the root. The formula for each iteration is:

x(i+1) = x(i) - (f(x(i))*(x(i)-x(i-1))/(f(x(i))-f(x(i-1))))

To perform four iterations of the Secant Method, we start with two initial values x(0) and x(1) and use the formula to calculate x(2), x(3), and x(4).

Iteration 1:

x(0) = 0.0000

x(1) = 8.0000

f(x(0)) = 0.0148

f(x(1)) = 65.67

x(2) = x(1) - (f(x(1))*(x(1)-x(0))/(f(x(1))-f(x(0))))

x(2) = 8.0000 - (65.67*(8.0000-0.0000))/(65.67-0.0148)

x(2) = 0.0148

Iteration 2:

x(1) = 8.0000

x(2) = 0.0148

f(x(1)) = 65.67

f(x(2)) = 1.3209

x(3) = x(2) - (f(x(2))*(x(2)-x(1))/(f(x(2))-f(x(1))))

x(3) = 0.0148 - (1.3209*(0.0148-8.0000))/(1.3209-65.67)

x(3) = -50.13

Iteration 3:

x(2) = 0.0148

x(3) = -50.13

f(x(2)) = 1.3209

f(x(3)) = 101.364

x(4) = x(3) - (f(x(3))*(x(3)-x(2))/(f(x(3))-f(x(2))))

x(4) = -50.13 - (101.364*(-50.13-0.0148))/(101.364-1.3209)

x(4) = 2.1883

Iteration 4:

x(3) = -50.13

x(4) = 2.1883

f(x(3)) = 101.364

f(x(4)) = 1.3209

The table is now complete with four iterations of the Secant Method.

User Henry Vonfire
by
7.6k points