Question

1. The voltage across a 5μ capacitor is v(t)=10 cos 6000t V. Calculate the current through it

Answer 1

The current through the capacitor can be found by differentiating the voltage with respect to time. Using the given voltage equation, we can calculate the current as i(t) = -60000C sin(6000t).

Step-by-step explanation:

The current through a capacitor is given by the derivative of its charge with respect to time. In this case, the voltage across the capacitor is given as v(t) = 10 cos(6000t) V. We can find the current by differentiating the voltage with respect to time:

i(t) = d/dt [Cv(t)]

Substituting the given voltage, we have:

i(t) = d/dt [C * 10 cos(6000t)]

i(t) = -C * 10 * 6000 sin(6000t)

So, the current through the capacitor is i(t) = -60000C sin(6000t).