Question

The maximum power supplied by any one generator is (6250kVA)(0.85)=5.31MW. Generator 3 will be the first machine to reach that limit. Generator 3 will supply this power at a frequency of

5.31 MW = (3.0 MW/Hz)(61 HZ - fₓᵧₛ)
fₓᵧₛ = 59.23 Hz
At the point the power supplied by Generators I and 2 is
P₁ = P₂ = sₚ₁(fᵦᵢₗ - fₓᵧₛ) = (2.5 MW/Hz0(61 Hz - 59.23 Hz) = 4.425 MW
The total power supplied by the generators at this condition is 14.16MW.

Answer 1

The power output of a hydroelectric generator can be calculated using the formula power = mgh, where m is the mass flow rate of water, g is the acceleration due to gravity, and h is the height of the reservoir.

Step-by-step explanation:

To compute the power output of a hydroelectric generator, you need to know the flow rate of water and the height of the reservoir. The power output can be calculated using the formula: power = mgh, where m is the mass flow rate of water, g is the acceleration due to gravity, and h is the height of the reservoir. For example, if the flow rate is 2,000 m³/s and the reservoir height is 50 m, then the power output would be approximately 1 GW. However, with an efficiency of 90%, the actual electrical power output would be 900 MW.