Final answer:
The average value of a sine wave with a peak-to-peak value of 88 V is zero when considering the full cycle. For practical purposes, the RMS value is used to represent the 'average' voltage in AC circuits, which would be approximately 31.11 V in this case.
Step-by-step explanation:
The student has asked about the average value of a sine wave with a peak-to-peak value of 88 V. In AC voltage, the voltage fluctuates sinusoidally over time and can be expressed as V = Vo sin 2πft, where V is the voltage at time t and Vo is the peak voltage. The average value of a sine wave over time, for a full cycle, is actually zero because the positive and negative halves of the cycle cancel each other out. However, when discussing average values in the context of AC voltage, we often refer to the root mean square (RMS) value, which provides a measure of the equivalent DC voltage that would deliver the same power to a load.
For a sine wave, the RMS voltage is Vo/√2, where Vo is the peak voltage. The peak voltage is half of the peak-to-peak voltage, so in this case, Vo would be 44 V (half of 88 V). Therefore, the RMS voltage would be 44 V / √2, which is approximately 31.11 V. This is not typically called the average value in physics, but it's the value that's typically used when calculating power in AC circuits.