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og(3x-2)<=2 4. logx+log(x-3)=1 5.-ln(1-2x)+1=g(x) III. Find the value of the following. log_(7)49 log_(27)3 log_(2)(1)/(128) log100 lne

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Final answer:

We used the properties of logarithms to find the value of various logarithmic expressions. The logarithm of a number raised to an exponent is the product of the exponent and the logarithm of the base number. In particular, we found log_7(49) to be 2, log_27(3) to be 1/3, log_2(1/128) to be -7, log(100) to be 2, and lne to be 1.

Step-by-step explanation:

The student's question involves solving logarithmic expressions and equations, which are a part of high school mathematics, particularly algebra and precalculus. We will go through the requested logarithmic values using the properties of logarithms.

Logarithmic Values:

  • log7(49): Since 49 is 7 squared, we use the property that the logarithm of a number raised to an exponent is the product of the exponent and the logarithm of the base number. Therefore, log7(72) = 2 * log7(7) = 2.
  • log27(3): 27 is 3 cubed, so we can write this as log27(31/3) which equals 1/3.
  • log2(1/128): Writing 128 as 27, we have log2(2-7) and thus this value is -7.
  • log(100): Since 100 is 10 squared, log(100) = log(102) = 2.
  • ln(e): The natural logarithm of e is 1, since e is the base of the natural logarithm. ln(e) = 1.

These calculations demonstrate the use of logarithmic properties including the power rule, the change of base, and the understanding that the natural logarithm of e is 1.

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