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If the Thevenin equivalent for a circuit is a 5.9V voltage source in series with a 12.9kΩ resistor, then what is the Norton equivalent resistance for this circuit in kilohms?

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Final answer:

The Norton equivalent resistance for a circuit with a Thevenin equivalent of a 5.9V voltage source in series with a 12.9kΩ resistor is 12.9kΩ.

Step-by-step explanation:

The Norton equivalent resistance for a circuit which has a Thevenin equivalent of a 5.9V voltage source in series with a 12.9kΩ resistor is the same as the Thevenin equivalent resistance. This equivalence is a fundamental aspect of Thévenin's and Norton's theorems, which state that for linear electrical networks with sources and resistances, the Thevenin and Norton equivalents are directly interchangeable.

In this case, since the Thevenin equivalent resistance is 12.9kΩ, the Norton equivalent resistance is also 12.9kΩ. It's important not to confuse resistance with other variables like current or voltage when converting between Thevenin and Norton equivalents; the resistances remain consistent across both forms.

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