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Find z such that 69% of the standard normal curve lies between -x and z. (Round your answer to two decimal places.)

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Final answer:

Using the z-table, calculated that the value of z is approximately 1.04.

Step-by-step explanation:

To find z such that 69% of the standard normal curve lies between -x and z, we first understand that the standard normal distribution is symmetrical around the mean.

Since 69% is close to the empirical rule's 68%, we might expect z to be close to 1.

However, because we are looking for a precise value and not using the empirical rule, we need to adjust this estimate.

First, we know that if 69% of the area is between -x and z, then the area to the left of z is 0.345 (half of 69%) plus 0.5 (the left half of the distribution), giving a total of 0.845 of the area under the curve.

By using a z-table or a standard normal distribution calculator, we find the z-score that corresponds with an area to the left of 0.845.

The z-table generally provides the area to the left of a z-score.

Looking this up, we find that z is approximately 1.04.

So z = 1.04 (rounded to two decimal places).

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