Question

a projectile is launched off an 80 foot high tower and reaches a peak height of 144 feet after 4 seconds. write an equation to find the height of the projectile at any given time. define any variables you use

Answer 1

The equation to find the height of a projectile at any given time is h(t) = -16t^2 + vt + s, where h(t) is the height at time t, v is the initial vertical velocity, and s is the initial height. For this specific scenario, the equation is h(t) = -16t^2 + vt + 80.

Step-by-step explanation:

The height of a projectile at any given time can be determined using the equation:

h(t) = -16t^2 + vt + s

where h(t) is the height of the projectile at time t, v is the initial vertical velocity, and s is the initial height.

In this case, the initial height is 80 feet and the projectile reaches a peak height of 144 feet after 4 seconds. Plugging these values into the equation, we get:

h(t) = -16t^2 + vt + 80